TreesBinary TreePost Order ProcessingOn this pagePost Order Processing or Bottom up recursion Traverse 563. Binary Tree TiltNoneAttemptedSolvedRevisitEasy2 solutionsexplanationanalysis1 playgroundRelated (1)Tilt of Binary TreeE563. Binary Tree TiltExplanationSolutions:1DFS (Recursive)2DFS (Iterative)Interactive VisualizationAnalysisPythondef findTilt(self, root: Optional[TreeNode]) -> int: def dfs(node): nonlocal tilt if not node: return 0 left_total = dfs(node.left) right_total = dfs(node.right) tilt += abs(left_total - right_total) return node.val + left_total + right_total tilt = 0 dfs(root) return tilt 110. Balanced Binary TreeNoneAttemptedSolvedRevisitEasy2 solutionsexplanationanalysis1 playgroundRelated (1)Balanced Tree CheckE110. Balanced Binary TreeExplanationSolutions:1DFS (Recursive)2DFS (Iterative)Interactive VisualizationAnalysisPythondef isBalanced(self, root: Optional[TreeNode]) -> bool: def dfs(node): if not node: return True, 0 left_result, left_height = dfs(node.left) right_result, right_height = dfs(node.right) node_height = 1 + max(left_height, right_height) if abs(left_height - right_height) > 1: return False, node_height return left_result and right_result, node_height return dfs(root)[0] Children Sum in a Binary TreeNoneAttemptedSolvedRevisitMedium2 solutionsexplanationanalysis1 playgroundChildren Sum in a Binary TreeExplanationSolutions:1DFS (Recursive)2DFS (Iterative)Interactive VisualizationAnalysisPythondef isSumProperty(self, root): def dfs(node): if not node: return 0, True if not node.left and not node.right: return node.data, True left_total, left_result = dfs(node.left) right_total, right_result = dfs(node.right) child_total = left_total + right_total return node.data, left_result and right_result and node.data == child_total return dfs(root)[1] 1973. Count Nodes Equal to Sum of DescendantsNoneAttemptedSolvedRevisitMedium2 solutionsexplanationanalysis1 playground1973. Count Nodes Equal to Sum of DescendantsExplanationSolutions:1DFS (Recursive)2DFS (Iterative)Interactive VisualizationAnalysisPythondef equalToDescendants(self, root: Optional[TreeNode]) -> int: def dfs(node): nonlocal count if not node: return 0 left_total = dfs(node.left) right_total = dfs(node.right) descendant_total = left_total + right_total count += descendant_total == node.val return node.val + descendant_total count = 0 dfs(root) return count 508. Most Frequent Subtree SumNoneAttemptedSolvedRevisitMedium2 solutionsexplanationanalysis1 playground508. Most Frequent Subtree SumExplanationSolutions:1DFS (Recursive)2DFS (Iterative)Interactive VisualizationAnalysisPythonimport collections def findFrequentTreeSum(self, root: Optional[TreeNode]) -> List[int]: def dfs(node): nonlocal max_freq if not node: return 0 left_total = dfs(node.left) right_total = dfs(node.right) total = node.val + left_total + right_total frequency[total] += 1 max_freq = max(max_freq, frequency[total]) return total frequency = collections.defaultdict(int) max_freq = 0 dfs(root) return [total for total, freq in frequency.items() if freq == max_freq] Manipulate Tree Transform to Sum TreeNoneAttemptedSolvedRevisitEasy2 solutionsexplanationanalysis1 playgroundRelated (1)Transform to Sum TreeETransform to Sum TreeExplanationSolutions:1DFS (Recursive)2DFS (Iterative)Interactive VisualizationAnalysisPythondef toSumTree(self, root): def dfs(node): if not node: return 0 left_total = dfs(node.left) right_total = dfs(node.right) total = left_total + right_total + node.data node.data = left_total + right_total return total dfs(root)